CS 610 Assignment 3 Solution fall 2020/2021
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CS 610 Assignment Solution fall 2021
Question No. 1
Suppose a multinational company has a computer between its office and a sub-office. The head office is currently using the IP address (192.16.12.0) of class C whereas
the sub-office is using the IP address (180.12.2.0) of class B. Due to increase
in number of its employees the company wants to create father subnets as per
following requirements
v For Head Office. 12 subnets each
having 9 hosts
v For Sub-office. 136 Subnets each
having 240 host
Considering
the above-mentioned scenario and requirements, you are required to answer the
following questions in the given table:
|
Sr. No |
Question |
Answer |
|
1 |
What will be Subnet
mask to fulfill the demand of a number of subnets and hosts for head office? |
255.255240 |
|
2 |
How many bits will be
borrowed to create the required number of subnets for the head office? |
04 |
|
3 |
What will be the valid
range of host address in the 4th subnet of head –office? |
192.16.12.48 to 192.16112.63 |
|
4 |
What will be the
Subnet mask to fulfill the demand of a number of subnets and hosts for
sub-office? |
255.255.255.0 |
|
5 |
How many bits will be
borrowed to create the required number of subnets for the sub-office? |
8 bits |
Question No.2
Suppose Alpha-Tech
company has a computer network and assigned a class B network address
180.10.2.0 and subnet mask as 255.255.0.0. in order to deal with the host
requirement the company wants to perform subletting among its departments i.e. Admin, Account,
Sales, HR and IT having the hosts requirements as 30,320,250,120 and 54
respectively.
Considering
the above-mentioned scenario and requirements, you are to fill the following
table:
|
Departments |
Required No. of Hosts |
No. of for subletting |
Subnet mask |
|
Admin |
30 |
11 |
255.255.255.224 |
|
Account |
320 |
7 |
255.255.254.0 |
|
Sales |
250 |
8 |
255.255.255.0 |
|
HR |
120 |
9 |
255.255.255.128 |
|
IT |
54 |
10 |
255.255.255.192 |
Class B
subnet mask 255.256.0.0
16 bits for
host
2^5 = 32 16- 5 = 11
2^9 = 512 16- 9 = 7
2^8 =256 16- 8 = 8
2^7 =
128 16- 7 = 9
2^6 = 64 16- 6 = 10